Surface.DrawBitmap(bitmap, new SKPoint()) Surface.Translate(-originalWidth / 2, -originalHeight / 2) Surface.Translate(rotatedWidth / 2, rotatedHeight / 2) Using (var surface = new SKCanvas(rotatedBitmap)) Var rotatedBitmap = new SKBitmap(rotatedWidth, rotatedHeight) Step 6: Close the image editor and check if the image is saved. Step 5: Save the changes by clicking on the Save icon located at the top of the window. Step 4: Rotate the image to your convenience by selecting the option under Rotate in the Arrange group menu. Int rotatedHeight = (int)(cosine * originalHeight + sine * originalWidth) Step 3: Double click on the image to enable the options to make changes to the image. Int rotatedWidth = (int)(cosine * originalWidth + sine * originalHeight) Slightly modified result: public static SKBitmap Rotate(SKBitmap bitmap, double angle)įloat sine = (float)Math.Abs(Math.Sin(radians)) įloat cosine = (float)Math.Abs(Math.Cos(radians)) Matthew's solution works for me too, but i had an issue when i tried to rotate bitmaps more than 90° or -90° (bitmap was drawed "out of display").
You can see this in the output image as it is actually cropped off a bit. As you can't actually change the dimensions of a bitmap once created, you have to create a new one. If the bitmap is 50x100, and then you rotate 90 degrees, the bitmap is now 100x50. The second "issue" is that you are rotating the image, but you are not changing the canvas dimensions. What I did was to create a NEW bitmap and then draw the decoded bitmap onto that. Thus, you still have the margins from the image below. You have basically taken an image, and then made a copy on draw it onto the first image. The reason for this (or yours not working as expected) is that you are rotating the bitmap on itself. Using (var surface = new SKCanvas(rotated)) Var rotated = new SKBitmap(bitmap.Height, bitmap.Width) Using (var bitmap = SKBitmap.Decode("test.jpg")) You may want to do something like this: public static SKBitmap Rotate()
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